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I read this article in The Guardian that said that black GOP support goes up as the density of the black population goes down. I mean by "density" the proportion of black population in an area. I have looked at data on the internet and it suggests that this is the case. For example, Trump got about 8% of the black vote nationally but only 3% of the vote in Detroit.

Why is this?

Article: https://www.theguardian.com/commentisfree/2020/feb/14/black-americans-are-not-a-monolithic-group-so-stop-treating-us-like-one

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    It's not really anything specifically about black people, Detroit is more dense than the US average and denser areas are less GOP, regardless of race. – dandavis Aug 21 at 7:28
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    aside: using an adjective (black) as a noun is incorrect (adjectives aren't plural) and often considered offensive; ask the shorts, the balds, and the olds. – dandavis Aug 21 at 7:30
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I'm not finding a systematic analysis of the data to address this question, but I suspect it results from the intersection of two sets of facts:

  1. "Today, 75 percent of African-Americans live in cities or suburbs. 15 percent live in smaller cities and towns, while just 10 percent live in rural areas, mainly in the South. (source)
  2. Trump won only 35 percent of the vote in urban areas but 62% in rural areas. (source)

Urban and rural voters have all kinds of strong differences in terms of general political attitudes and values. (source) So my hypothesis would be that those districts with a high density of black voters are more likely to be urban, and that the black vote follows the general voting trend of urban/Democrat vs. rural/Republican. Perhaps someone more ambitious and adept with data can test this directly.

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