TL;DR: It's possible that Begich was the Condorcet winner (with an overall Condorcet ranking of Begich > Peltola > Palin), but we can't know for sure without knowing everyone's second choices.
We also can't rule out the possibility of a non-transitive cycle where Begich beat Peltola, and Peltola beat Palin, but Palin beat Begich.
Assigning variables to your question marks, we get a ballot set of:
- 27053: Begich > Palin
- 15467: Begich > Peltola
- 11290: Begich
- a: Palin > Begich
- b: Palin > Peltola
- 58973-a-b: Palin
- c: Peltola > Begich
- d: Peltola > Palin
- 75799-c-d: Peltola
There are three pairwise contests to consider:
Palin vs. Peltola
This one is easy because it's the one that actually got counted. Peltola won, by a margin of 5240 votes.
- 91266: Peltola
- 86026: Palin
However, this contest has no bearing on whether Begich would be the Condorcet winner.
Begich vs. Peltola
The total vote count is:
- 53810+a: Begich
- 75799+b: Peltola
The result comes down to Palin voter's second choices (a and b):
- Begich wins if a-b > 21989
- Peltola wins if a-b < 21989
If all 58973 of Palin's first-choice voters expressed a second choice, then Begich would need at least 40482, or 68.6% of those votes, in order to win the pairwise contest.
For comparison, among voters who ranked Begich first, Palin got 63.6% of those ballots that expressed a second choice, or 60.7% of ballots if those who didn't make a second choice flipped a coin.
So Begich winning this contest would require Palin voters to have noticeably more party loyalty than Begich voters. But this would easily be explainable with a framing of Begich as a moderate candidate compared to more a more solidly right-wing Palin.
Begich vs. Palin
The total vote count is:
- 53810+c: Begich
- 58973+d: Palin
The result comes down to Peltola voters' second choices.
- Begich wins if c-d > 2581.5
- Palin wins if c-d < 2581.5
If all 75799 of Peltola's voters expressed a second choice, then Begich would need at least 40481, or 53.4%. This is a rather close contest, and it's hard to tell who would win.